Google Google is a global tech giant headquartered in California, USA and currently has several referral opportunities available! Recently, Google Cloud has resumed some of its recruiting, so if you want to jump into a new job at the end of the year or get your year-end bonus after the year-end, hurry up and learn about the internal referral process and internship positions.
Why inbound?
While official resumes are often dropped like a stone, inbound recruiting can at least get a recruiter through the process, and if you're lucky, the inbound recruiter will give you interview advice.
Google Inbound Process
- Pick 1-3 suitable positions and find Googlers who are willing to inbound.
- Googler Submit your resume, email and reason for inbound reasoning in the internal system and the system will automatically send you an inbound email.
- Inbound emails with invitation links are valid for 30 days for up to 3 global positions.Before applying, please make sure that all Minimum Qualifications have been met.
- Googler tracks the status of your application in the system and you can wait to be contacted by a recruiter.
FAQ
- Recruiter How long to contact?
Depending on the situation, it can take as little as a week or as long as a couple of weeks, and in most cases the recruiter will inform the inductee of the result. - Any Singapore EPs?
There are many Googlers who hold EPs and the recruiter will ask about your visa status after contacting them. - When can I reapply if I did not get an interview?
There is a 90-day wait for the same position; other positions can be reapplied for after 30 days. Competition is fierce, so don't be discouraged.
Why go for a Google referral?
Submitting your resume directly often yields no response. A referral ensures a recruiter reviews your profile and may offer guidance.
Google Referral Process (English)
- Monitor the careers site and choose up to three suitable roles.
- Ask a Googler to submit your details and referral reason in the internal system.
- You'll receive an email with a referral link valid for 30 days; select up to three global positions. Ensure you meet all Minimum Ensure you meet all Minimum Qualifications before applying.
- The Googler can track your application; then simply wait for the recruiter to contact you.
FAQ (English)
- How long before a recruiter contacts me?
It varies: from one week to several weeks. Recruiters typically update the referrer on your status. - Is Employment Pass (Singapore) available?
Yes. Many Googlers hold EPs; the recruiter will discuss visa sponsorship if needed. - When can I reapply if I don't get an interview?
For the same role, wait 90 days; otherwise, you can reapply after 30 days.
Google Intern OA Real Questions Sharing
Google OA uses the CodeSignal platform, and brushing up on LeetCode Medium is sufficient. The following two questions are from the real written test.
Online Assessment 1
Given an array of length N points and a string of the same length tokens, each position is either empty ('.') , or contains a tag ('T'). Calculate the total score:
- Each cell containing a marker gets
points[i]Points. - One additional point is awarded for each two adjacent cells containing markers.
def solution(points, tokens): total = 0
total = 0
n = len(points)
for i in range(n).
if tokens[i] == 'T'.
total += points[i]: if tokens[i] == 'T'.
for i in range(n - 1): if tokens[i] == 'T': total += points[i]: points[i]
if tokens[i] == 'T' and tokens[i+1] == 'T'.
total += 1
return total
Online Assessment 2
Given an array of numbers, select up to three numbers in their original order to form the largest possible number. The selected numbers need not be adjacent.
- The enumeration picks all combinations of 1, 2 or 3 bits.
- Maintain the maximum value by collapsing the numbers in the combination into integers.
from itertools import combinations
def solution(digits): max_num = 0
max_num = 0
for r in range(1, 4): for combo in combinations(digits, r): max_num = 0
for combo in combinations(digits, r): num = int(''.join(map(strings, combo)).
num = int(''.join(map(str, combo)))
max_num = max(max_num, num)
return max_num
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For Google inbound, OA assistance, or interviewing agents, please Contact UsThe first thing you need to do is to get your hands dirty. But there is no charge for not passing, and strength guarantees passing.
