
Meta interview The whole thing comes down to a total of 5 rounds.
Step 1: Screening (initial screening)This round evaluates the candidate on four dimensions: ability to parse the problem, ability to code, ability to validate the code, and ability to communicate, which is generally remote.
Once you've passed Step 1, it's time to move on to Step 2 Full Loop interviews, which are usually on-site
Coding Interviews(2-3 rounds of 45 minutes each): 3 rounds for interns and fresh grad, and 2 rounds for senior staff above E4.In Coding interviews, it may start with MEDIUM difficulty questions, but the interviewer will randomly change the requirements to increase the difficulty, such as a leetcode problem about balancing parentheses in a string. The normal practice would be to use a stack to solve it, but the interviewer will increase the difficulty by directing you to find a solution that doesn't take up extra space.
System Design Interview(1 round, 45 minutes): This round will be an in-depth discussion where the interviewer will carefully evaluate the candidate's ability to design complex systems. The content will be customized to the position applied for, whether the position is related to systems, product or front-end design. The key point of this round is that there is no single right answer, as meta's system design interviews are known for their open-endedness, allowing for a wide range of potential answers
Behaviour Interview(1 round, 45 minutes): Interviewers will dig deeper into the candidate's background, review past projects, and ask the candidate to tell stories of growth and conflict, etc.
Team MatchingAfter all the interviews, the meta will match the candidate with the right team, it's a two-way questioning and matching process to make sure the candidate is a good match for the team's skills and culture, this round is still quite important to determine if you can get into the team or product line of your choice!
Meta Interview Question
Coding 1
Given a string s consisting of left parentheses, right parentheses, and lowercase letters, we need to remove the minimum number of parentheses (either left or right, in any position) so that the remaining parenthesized string is valid, and then return any valid result string. The idea is that by traversing twice, we ensure that the parentheses are legal with the least amount of deletion, while retaining all the letters, resulting in a valid string. The final follow up asks how to return all possible results if there are multiple valid solutions.
Thoughts:By traversing twice, we ensure that the parentheses are legal with a minimum of deletion operations, while retaining all the letters to end up with a valid string. The final follow up asks how to return all possible results if there is more than one valid solution
Coding 2
Given a set of video durations and user attention durations, the requirement is to select a subset of videos such that the sum of the durations of any two consecutive videos does not exceed the user's attention duration while maximizing the total viewing duration.
Thoughts:We define dp[i][j] to denote the maximum viewing duration when the previous i videos are considered and the remaining attention duration is j. For state transfer, for each video, we have two choices: skipping keeps the original state; selected requires ensuring that the duration sum with the last selected video does not exceed the attention constraint, and updating the state if it is satisfied. To handle the constraints of consecutive videos, the selection history can be tracked by additionally recording the duration of the last selected video in the state, or by using an auxiliary array. The final solution is the maximum of all possible states.
Conclusion
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