The Ultimate Guide to the Anthropic OA: From OA to Offer

Anthropic, the AI research company behind the Claude language model series, has quickly become a leading voice in the safe and interpretable AI movement. Their mission is grounded in alignment and responsibility, and that philosophy carries into their hiring process. Anthropic OA for software engineering roles reflects their high technical standards. Candidates are evaluated not only on their algorithmic problem-solving ability, but also on writing clean, maintainable code that demonstrates systems-level thinking, privacy awareness, and performance trade-offs.

The Ultimate Guide to the Anthropic OA: From OA to Offer

Below are three representative Anthropic-style OA questions, along with insights and code samples.

Question 1: Sensitive Data Redactor

Problem:
Write a function that scans a block of user-generated text and redacts sensitive entities such as email addresses, phone numbers, and credit card numbers by replacing them with [REDACTED].

Input:

text = "Contact me at john.doe@example.com or call 555-123-4567. My Visa is 4111-1111-1111-1111."

Expected Output:

"Contact me at [REDACTED] or call [REDACTED]. My Visa is [REDACTED]."

Question 2: Token Budget Optimizer

Problem:
You are given a list of generated text segments from an LLM, each with a token count and a relevance score. Your goal is to return the most relevant subset of segments such that their combined token count does not exceed a given limit.

This is a variant of the 0/1 Knapsack Problem.

Input:

segments = [
    {"text": "Answer A", "tokens": 5, "score": 8},
    {"text": "Answer B", "tokens": 7, "score": 13},
    {"text": "Answer C", "tokens": 4, "score": 6}
]
limit = 10

Expected Output:
A subset (e.g., ["Answer A", "Answer C"]) maximizing score under token limit.

Reference Code:

def token_budget_optimizer(segments, limit):
    n = len(segments)
    dp = [[0] * (limit + 1) for _ in range(n + 1)]

    for i in range(1, n + 1):
        tokens = segments[i-1]['tokens']
        score = segments[i-1]['score']
        for j in range(limit + 1):
            if tokens <= j:
                dp[i][j] = max(dp[i-1][j], dp[i-1][j-tokens] + score)
            else:
                dp[i][j] = dp[i-1][j]

    # Reconstruct the chosen subset
    res = []
    j = limit
    for i in range(n, 0, -1):
        if dp[i][j] != dp[i-1][j]:
            res.append(segments[i-1]['text'])
            j -= segments[i-1]['tokens']
    return res[::-1]

Question 3: Rate-Limited Logger

Problem:
Design a logging system that prints incoming messages only if the same message hasn’t been printed in the last 10 seconds. This simulates logging at scale while avoiding log flooding.

Input:

log_system.should_log(1, "error: out of memory")   # True
log_system.should_log(3, "error: out of memory")   # False
log_system.should_log(11, "error: out of memory")  # True

Output:
Return True if the message should be printed; else False

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