夢想加入 Figma 來塑造協同設計的未來？Figma OA 是第一道關卡，測試您在 UI/UX 情境下的編碼技巧和 Figma 工具的精通程度。這是一項獨特的挑戰，但 programhelp 已經幫助數以千計的人通過了技術 OA！我們以真實的範例問題和實用的預備技巧來分析 Figma OA，幫助您脫穎而出，更接近您夢想中的工作機會。
Figma OA 面試準備
Figma 的 OA 通常在 CodeSignal 或 HackerRank 等平台上進行，時間為 60-90 分鐘，包含 2-3 個融合編碼和設計情境的任務。使用免費的 Figma 帳戶練習 LeetCode 中等問題 (陣列、字串) 和 Figma 基本知識 (元件、原型設計、自動佈局)，熟悉平台除錯工具和 Figma 的協作功能 (如版本歷史)。確保穩定的網際網路和編碼設定。programhelp 量身訂做的輔導可協助您有效掌握編碼和 Figma 技能！網頁:0,5
Figma online assessment Sample Questions
Algorithm-Focused: Component Usage Counter
Description: Given a list of Figma design components used in a project (with IDs and names), count the occurrences of each unique component ID.
Example:
[{id: "c1", name: "Button"}, {id: "c2", name: "Icon"}, {id: "c1", name: "ButtonV2"}], Output {"c1": 2, "c2": 1}.Approach: Use a hash map to track component ID frequencies. Time complexity: O(n).
def count_components(components):
count = {}
for comp in components:
count[comp["id"]] = count.get(comp["id"], 0) + 1
return countDesign Tool Application: Figma Layout Validation
Description: Given a Figma frame’s elements with properties (e.g., width, height, auto_layout), validate if all elements fit within theframe’s width using auto-layout constraints.
Example:
frame={"width": 400}, elements=[{"width": 150}, {"width": 200}], Output True (150 + 200 ≤ 400).Approach: Sum element widths and compare against the frame’s width, considering auto-layout padding. Time complexity: O(n).
def validate_layout(frame, elements, padding=10):
total_width = sum(el["width"] for el in elements) + padding * (len(elements) - 1)
return total_width <= frame["width"]Scenario-Based: Prototype Interaction Log
Description: Given a log of Figma prototype interactions [[“user1”, “click:button1”], [“user2”, “hover:menu”]], count interaction types (e.g., click, hover) per user.
Example:
{"user1": {"click": 1, "hover": 0}, "user2": {"click": 0, "hover": 1}}.Approach: Use a nested dictionary to track user interactions, parsing logs by “:”. Time complexity: O(n).
def analyze_interactions(logs):
result = {}
for user, entry in logs:
action = entry.split(":")[0]
if user not in result:
result[user] = {"click": 0, "hover": 0}
result[user][action] += 1
return result全方位支援您的夢想！
從代理訪談和代碼編寫到考試支援和出國留學協助、 Programhelp 是您學業和職業成功的一站式解決方案。現在就聯繫我們，開始您的成功之旅！
